Question

an object of size 7cm is placed at 27cm in front of a concave mirror of focal length 18cm. at what distance from the mirror should a screen be placed, find the size and nature of image?
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Answer 1

ANSWER⇩⇩

⇝GIVEN

h = 7cm

u = -27cm

f = -18cm

⇝TO FIND

v = ?

h = ?

m = ?

⇝FORMULA USED

$\frac{1}{f} = \frac{1}{v} + \frac{1}{u}$

⇝LET'S BEGIN

$\frac{1}{ - 18} = \frac{1}{v} + \frac{1}{ - 27}$

$\frac{1}{v} = \frac{1}{ - 18} + \frac{1}{ 27}$

$\frac{1}{v} = \frac{ - 3 + 2}{54}$

$\longmapsto \boxed{\: \pink {\frac{1}{v} = - 54cm}}$

NOW,

$\frac{h'}{h} = \frac{ - v}{u}$

$\frac{h'}{7} = \frac{ - 54}{ - 27}$

$: \longrightarrow \boxed{ \green{h' = - 14cm}}$

THEREFORE, WITH THIS

THE IMAGE WILL BE REAL , INVERTED AND ENLARGED IMAGE.

$\large \mathfrak\star\purple{HOPE \: \: IT \: \: HELPS }\star$