an object oh height 4 cm is placed at a distance of 15 cm in front of a concave lens of power ,-10 diopters. find the size of the image.
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Answered by
11
given
h = 4 cm
u = 15 cm
p = -10 D
we know that
P = 100\f( in cm)
-10 = 100\f
therefore f = -10 cm
1\v - 1\u = 1\f
1\v - 1\15 = 1\-10
v = -6 cm
h'\h = v\u
h' = -6\-15*4
h' = 1.6 cm
therefore object height is 1.6 cm.
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habiba55:
but the answer is 1.6cm it is given in the answer sheet
Answered by
1
Height of object = 4cm
U =-15cm
P =1/f
-10f =1
f=-1/10x 100cm
f=-10cm
1/v=-1/10-1/15=-5/30
v=-6cm
m=v/u =6/15
Height of image =v/u x height of object
6/15 x 4 = 24 / 15 =1.6cm
Therefore the height of the image is 1.6 cm
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