An object placed in front of a diverging mirror at a distance of ...
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An object placed in front of a concave mirror at a distance of x cm from the pole gives a 3 times magnified real image. If it is moved to a distance of (x+5)cm, the magnification of the image becomes 2.
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Diverging mirror is also known as Convex mirror.
u= -30
h of image= 1/5(h of object)
Since the image is erect , h of image is positive.
Now, let height of object be x and h of image therefore will be x/5
we know that -v/u = h(i)/h(o)
:. -v/-30 = (x/5)/x
-v = -30x/5x
-v = -6
:. v = 6
The image is formed 6 cm behind the mirror.
Now, v=6 u= -30
Using the mirror formula 1/v + 1/u = 1/f
1/6 + -1/30 = 1/f
5-1/30 =1/f
4/30 = 1/f
2/15 =1/f
f=15/2 or f= 7.5 cm
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