AN OBJECT RISES VERTICALLY UPWARDS TO A HEIGHT OF 100 M IN 5 SECONDS,THEN COMES BACK AT THE SAME POSITION AFTER ANOTHER 5 SECS . FIND THE DISTANCE TRAVELED , DISPLACEMENT , AVERAGE SPEED AND AVERAGE VELOCITY OF THE OBJECT.
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Explanation:No displacement therefore displacement = o
Since the distance travelled is 100 m up and 100 m down therefore total distance travelled =200 m
Average speed = total distance / total time
= 200/10
=20 m/s
Average Velocity = Total Displacement/Time
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