Question

AN OBJECT RISES VERTICALLY UPWARDS TO A HEIGHT OF 100 M IN 5 SECONDS,THEN COMES BACK AT THE SAME POSITION AFTER ANOTHER 5 SECS . FIND THE DISTANCE TRAVELED , DISPLACEMENT , AVERAGE SPEED AND AVERAGE VELOCITY OF THE OBJECT.

Answer 1

Answer:

Explanation:

Hope it helps you....

Answer 2

Answer:

Explanation:No displacement therefore displacement = o

Since the distance travelled is 100 m up and 100 m down therefore total distance travelled =200 m

Average speed = total distance / total time

= 200/10

=20 m/s

Average Velocity = Total Displacement/Time