Question

An object starting from rest attains a speed of 25m/s after travelling a distance of 50 m. calculate the accelaration produced and the total time taken to cover that distance. ​

Answer 1

Explanation:

using 3rd law of motion

v²= u²+2as

since the object starts from rest so it's initial velocity will be zero

v²= 2as

(25)²= 2×a×50

25×25/100= a

a= 25/4

a= 6.25 m/ sec²

Now we found the value of t for this using 1 at law of equation of motion we have

v= u + at

since the object start to move from rest so it's initial velocity will be zero

V = at

25 = 6.25 × t

t = 4 second

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Answer 2

Answer:

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