Question

The number of electrons with azimuthal quantum number l=1 and l=2 for Cr in ground state respectively are:

Answer 1

Electronic configuration of

24Cr=1s2,2s2,2p6,3s2,3p6,4s1,3d5

Given, azimuthal quantum number (l)=1⇒ p-orbital

azimuthal quantum number (l)=2⇒d−orbital. So, number of elections in p = 12 and number of electrons in d - orbital = 5.

Answer 2

Answer:

Explanation:

Electronic configuration of

Cr(24)=1s2  2s2  2p6  3s2  3p6  4s1  3d  5

Given, azimuthal quantum number (l)=1⇒ p-orbital

azimuthal quantum number (l)=2⇒d−orbital. So, number of elections in p = 12 and number of electrons in d - orbital = 5.