An object starting from rest increases its velocity to 48m/s in 4 sec. What is it's acceleration ?????
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Answered by
1
Hi Dear !
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Here, Initial Velocity (u) = 0 m/s
Final Velocity (v) = 48 m/s
time taken (t) = 4 seconds
acceleration (a) = ?
Using v = u + at
48= 0 + 4a
48 = 4a
a = 48/4
a = 12 m s^-2
______________________________________________________________
Here, Initial Velocity (u) = 0 m/s
Final Velocity (v) = 48 m/s
time taken (t) = 4 seconds
acceleration (a) = ?
Using v = u + at
48= 0 + 4a
48 = 4a
a = 48/4
a = 12 m s^-2
Answered by
1
Hello Friend!
Here, Initial Velocity (u) = 0 m/s(object starts from rest)
Final Velocity (v) = 48 m/s
time taken (t) = 4 seconds
acceleration (a) = not given
so to find the acceleration, we use the formula given below:
v = u + at
48= 0 + 4a
48 = 4a
a = 48/4
a = 12 m s^-2
HOPE THIS ANSWER HELPED YOU,,,,PLEASEE MARK AS BRAINLIESTT!!
Here, Initial Velocity (u) = 0 m/s(object starts from rest)
Final Velocity (v) = 48 m/s
time taken (t) = 4 seconds
acceleration (a) = not given
so to find the acceleration, we use the formula given below:
v = u + at
48= 0 + 4a
48 = 4a
a = 48/4
a = 12 m s^-2
HOPE THIS ANSWER HELPED YOU,,,,PLEASEE MARK AS BRAINLIESTT!!
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