Question

An object starting from rest moves with the uniform acceleration and travels a distance 45m in 8th second .find its acceleration?

Answer 1

$s = 0.5 \times a \times {t}^{2}$
s equals distance covered (45 m)
a equals acceleration (TBD)
t equals time interval (8 secs)

Answer 2

Answer: Distance = 45m

Time =8sec

To find it's acceleration

S(t) =u +1/2a(2t-1) (this is a formula)

45m= 0+1/2a(2×8-1)

45=0+1/2a×15

90/15=a

a=6 (this is ur answer)

Thanks!!!!!

Explanation: