An object starting from rest travels 20m in first 2s and 160m in next 4s. What will
be the velocity after 7s from the start?
Answers
Answered by
0
Answer:Correct option is
D
70
From s=ut+
2
1
at
2
In first 2 s,
s=20m
20=
2
1
a(2)
2
=2a
a=10 m/s
2
Velocity at the end of 2 s is
v=u+at=0+10×2=20m/s
In next 4s, s=ut+
2
1
a
′
t
2
160=20×4+
2
1
a
′
(4)
2
80=8a
′
a
′
=10 m/s
2
It shows that acceleration is uniform. From v=u+at
v=0+10×7=70 m/s
Answer: (D) 70
Explanation:
Answered by
3
After a = 10m/s square
By 2nd equation of motion,
v = u+at
v = 0 + 10 × 7
v = 70 m/s
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