An object starting from rest travels 40m in the first 2s and 240 m in the next 4s. What will be the velocity after 9s from the start?
Answers
Answered by
1
Answer:
hope it's helpful to you
Explanation:
From s=ut+
2
1
at
2
In first 2 s,
s=20m
20=
2
1
a(2)
2
=2a
a=10 m/s
2
Velocity at the end of 2 s is
v=u+at=0+10×2=20m/s
In next 4s, s=ut+
2
1
a
′
t
2
160=20×4+
2
1
a
′
(4)
2
80=8a
′
a
′
=10 m/s
2
It shows that acceleration is uniform. From v=u+at
v=0+10×7=70 m/s
Answered by
0
Answer:
70
Explanation:
From s=ut+
2
1
at
2
In first 2 s,
s=20m
20=
2
1
a(2)
2
=2a
a=10 m/s
2
Velocity at the end of 2 s is
v=u+at=0+10×2=20m/s
In next 4s, s=ut+
2
1
a
′
t
2
160=20×4+
2
1
a
′
(4)
2
80=8a
′
a
′
=10 m/s
2
It shows that acceleration is uniform. From v=u+at
v=0+10×7=70 m/s
Answer: (D) 70
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