Question

an object starting from rest travels with an acceleration of 5m/s^2 what will be Alo ts velocity after 3 seconds​

Answer 1

v=u+at

u=0

=0+5m/s²×60s

a=5m/s²

=0+300m/s

t=1 min

So, t=60sec

=300m/s

s=ut+1/2at²

=0×60+1/2×5×60²

=9000m

Explanation:

Hope this answer will be helpful..

Answer 2

❑ CORRECT QUESTION ❑

An object starting from rest travels with an acceleration of 5m/s what will be it's velocity after 3s?

★ GIVEN :

• Initial velocity (u) = 0 m/s

• Acceleration (a) = 5 m/s²

• Time (t) = 3 seconds

★ TO FIND :

• Final velocity (v)

★ SOLUTION :

We have :-

$➣\begin{gathered}\underline{\boldsymbol \color{fuchsia}{First\: Equation \:of\: Motion :}} \\\end{gathered}$

$\huge\color{blue} { \boxed {\boxed{ \bf\color{blue}{v =u + at }}}}$

✯ WHERE :

• v = final velocity

• u = initial velocity

• a = acceleration

• t = time

━━━━━━━━━━━━━━━━━━━━━━━━━━

♣ Putting all values :

$➡ \: \tt{v = 0 + \bigg(5 \times 3 \bigg)}$

$➡ \: \tt{v = 0 + 15}$

$➥ \: \boxed{ \tt\color{red}{v = 15}}$

━━━━━━━━━━━━━━━━━━━━━━━━━━

★ ANSWER :-

• Final velocity after 3 seconds is 15 m/s

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✪ Know More ✪

✦ First equation of motion :-

$\large\color{grey} { \boxed {\underline{ \bf\color{grey}{v =u + at }}}}$

Where :-

• v = final velocity

• u = initial velocity

• a = acceleration

• t = time taken

✦ Second equation of motion :-

$\large\color{grey} { \boxed {\underline{ \bf\color{grey}{ s\: =\: ut\: +\: ½\: at² }}}}$

Where :-

• s = distance covered

• u = initial velocity

• t = time taken

✦ Third equation of motion :-

$\large\color{grey} { \boxed {\underline{ \bf\color{grey}{ v²\: -\: u²\: =\: 2as}}}}$

Where :-

• v = final velocity

• u = initial velocity

• a = acceleration

• s = distance covered

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