an object starting from the rest a travels 20 meters in first 2 seconds and 160 meter in next 4 seconds what will be the velocity after 7 seconds from the starts
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Explanation:
total distance =S=(20+160)m=180m
total time=T=(2+4)s=6s
Acceleration=a
Initial velocity=u=0 ( as it was in rest)
A.T.P.
S = ut + (1/2)at^2
180 = 0×6 +(1/2)×a×6×6
180 = 18a
a = 10 m/sec sq.
hence, velocity at 7 sec= u+at
=0+10×7
=70 m/sec
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