An object starts from rest and is uniformly accelerated so that its speed is 60 m/s after 20s. If it travels with this speed for 40 s and is then brought to rest by a uniform retardation in 30 s. Sketch the velocity-time graph and calculate the acceleration, the retardation and the total distance travelled.
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Answer:
acceleration=3m/s²
retardation= -4/3m/s²
total distance=1200m
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