An object starts movinh from rest on straight line path with uniform acceleration and covers a distance of 100m in first 10s The distance it covers in next 5s
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50m is distance is covered
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s=at²/2. (becuz u=0)
then a =2s/t²=200/100=2m/s
then distance covered in next five seconds = distance in 15sec. -dist.in 10 sec.
a(t'²-t²)/2 = (225-100)×2/2= 125 metre
then a =2s/t²=200/100=2m/s
then distance covered in next five seconds = distance in 15sec. -dist.in 10 sec.
a(t'²-t²)/2 = (225-100)×2/2= 125 metre
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