Question

An object starts to slide over a horizontal surface with an antenatal velocity of 0.5 m/s. Due to friction, its velocity decreases at a rate of 0.05 m/s². How much time will it take for the body to stop?

Answer 1

Answer:

time = 10 seconds

Explanation:

u(initial velocity) = 0.5 m/s

v(final velocity)   = 0 since the object stops

a(acceleration)   =  - 0.05 m/s^2

we know that,

a = v-u/t

t = v-u/a = 0 - 0.5/-0.05 = -0.5/-0.05*100/100 = -50/-5 = 10

Answer 2

Answer:

Given :-

initial velocity = 0.5 m/s

final velocity = 0 m/s

acceleration =  - 0.05 m/s²

Formula to be used :-

v = u + at

How to find time :-

t = v-u/a = 0 - 0.5/-0.05 = -50/-5 = 10 s

Hence the object will stop in 10 s.

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