an object takes 5 seconds to reach the Ground from a height of 5m on the planet what is the value of g on the planet
Answers
Answered by
2
=ut + 1/2 * (at^2)
u=0
so
5 = (a*5*5)/2
So
a= 10/25
a= 0.4 m/s^2.
Answered by
4
We know that
s=ut+1/2(a×t^2)
here u=0.
t=5sec and
s=5m
5=0+(a×5×5)÷2
=> 10=25a
=> a= 0.4
hence acceleration,or g = o.4 m/s^2.
s=ut+1/2(a×t^2)
here u=0.
t=5sec and
s=5m
5=0+(a×5×5)÷2
=> 10=25a
=> a= 0.4
hence acceleration,or g = o.4 m/s^2.
Similar questions