An object thrown in downward direction from height 10m with initial velocity of 15m/s strikes the ground and bounces back to height of 12m determine the percentage loss of its energy during colliding with ground
Answers
Answered by
1
mgh + 1/2mv^2
100m + 112.5m = 212.5m
it bounced to 12m therefor energy 120m
*100[212.5 - 120]/212.5
43.52%
100m + 112.5m = 212.5m
it bounced to 12m therefor energy 120m
*100[212.5 - 120]/212.5
43.52%
Similar questions