Physics, asked by gayathrizz0210, 6 months ago

An object thrown upward from ground is caught back by the thrower after 8 sec. Find velocity of projection.
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Answers

Answered by dualadmire
0

Given:

Time after which the object is caught by the thrower = 8 sec

To find:

Velocity of projection

Solution:

The time of descent of the object = Time of ascent = 1/2 of total time

Time taken for the object to go up = 8/2 = 4 sec

Using the formula v = u + at

Since when the object reaches the highest point, it velocity is 0

0 = u - 9.8*4

u = 39.2 m/s

Therefore the velocity of projection will be 39.2 m/s.

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