An object thrown upward from ground is caught back by the thrower after 8 sec. Find velocity of projection.
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Given:
Time after which the object is caught by the thrower = 8 sec
To find:
Velocity of projection
Solution:
The time of descent of the object = Time of ascent = 1/2 of total time
Time taken for the object to go up = 8/2 = 4 sec
Using the formula v = u + at
Since when the object reaches the highest point, it velocity is 0
0 = u - 9.8*4
u = 39.2 m/s
Therefore the velocity of projection will be 39.2 m/s.
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