Question

An object thrown vertically up with a velocity of 10 m/s. Calculate the maximum height it rises. Take g= 9.8 m/s^2​

Answer 1

Answer:

1.43 sec

Step-by-step explanation:

Distance travelled, s = 10 m

Final velocity, v = 0 m/s

g = -9.8 m/s

2

1) Using,

v

2

−u

2

=2gs

u

2

=196

u=14m/s, where u is the velocity with which the object is thrown upwards.

2) Using,

v=u+gt

t=

g

v−u

=1.43 sec