Question

An object thrown vertically upward and rises to a height of 10m find initial velocity of object second time taken by object reaching the highest time please give answer

Answer 1

Let velocity of object is u

we know, at 10m height object will be rest .

so, final velocity = 0

A/C to kinematics equations,

v² = u² + 2aS

0 = u² +2(-g) × 10

0 = u² - 2 × 100

u² = 200

u = 10√2 m/s

Time taken by the object to reach the highest point is t

v = u + at

0 = 10√2 - 10t

t = 10√2/10 sec

t = √2 sec