An open metallic bucket is in the shape of a frustum of a cone if the diameter of the two circular ends of the bucket are 45 cm and 25 cm and the vertical height of the bucket is 24 cm find the area of metallic sheet used to make the bucket also find the volume of the water it can hold use pi equal to 22 by 7
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Answer:area =3351.07 cm2
Vol. =23.7lit.
Step-by-step explanation:
Firstly we have to find the slant height of the frutum
.... Calcute it
Slant height =26cm
Now,area of. Metallic sheet =csa of frustum +area of Base of frustum
PieL(r1 +r2) +pie r2(25)
Calculate it...
3351.07cm2
Now for vol.,
1/3pieh(r2+r2+rr)
Put values and calculate it,
It come 23.7...lit.
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