An object thrown vertically upwards reaches a height of 500 m. what was its initial velocity?How long will the object take to come back to the earth?Assume g = 10 m/s2.
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Answer:
let 'u' is the initial velocity and 'v' be the final
Explanation:
then from Newton's law,
(u^2)-(v^2)=2as
or,{(u)^2}-0=2×10×500
or,u^2=(10000)
or,u=100
now,
(u-v)/a=t
then,t=(100-0)/10
=10sec
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Answer:
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Explanation:
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