Question

An object thrown vertically upwards reaches a height of 500m. What was it's initial velocity? How long will it take to come back to the earth? Assume g=10 m/s^2.

Answer 1

$v^{2} = u {}^{2} + 2as$

Answer 2

hey friend ....


Nasra here....


....here's yr answer...


......



Given:
S=500m
u=?=0
v=?
g=a=10m/s2



as we know....


v2=u2+2as


therfore...putting those values...


v2=0+2*10*500


v2=10000


$\sqrt{10000} \\ \\ = 100m \div s {}^{2}$


v=100m/s2


hence ....


we know that...


v=u+at



therfore. ...putting those values....


100=0+10*t


10t=100


therefore....



t=10sec....(answer)....



hope helped...


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