an object travel 16 m in4 second and then another 16m in 2 second what is the average speed of the object
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Distance travelled by 1st object,d1 = 16m
Time taken by 1st object,t1 = 4s
Distance travelled by 2nd object,d2 = 16m
Time taken by 2nd object,t2 = 2
Therefore,
Average speed = (Total distance travelled)/(Total time taken)
=(16+16)/(4+2)
=32/6
=5.33m/s
Hope it helped you.
Mark as Brainliest answer.
Time taken by 1st object,t1 = 4s
Distance travelled by 2nd object,d2 = 16m
Time taken by 2nd object,t2 = 2
Therefore,
Average speed = (Total distance travelled)/(Total time taken)
=(16+16)/(4+2)
=32/6
=5.33m/s
Hope it helped you.
Mark as Brainliest answer.
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