rationalise the denominator of 1 / 2 + under root 3
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hey dear
here is your answer
Solution
1 /2 +√3
= 1 / 2+√3 * 2-√3 / 2-√3
= 2-√3 / (2)^2 - ( √3)^2
in this we use identity ( a+b ) (a-b) = a^2 -b^2
2- √3 / 4- 3
= 2-√3 /1.
hence answer is 2-√3
hope it helps
thank you
here is your answer
Solution
1 /2 +√3
= 1 / 2+√3 * 2-√3 / 2-√3
= 2-√3 / (2)^2 - ( √3)^2
in this we use identity ( a+b ) (a-b) = a^2 -b^2
2- √3 / 4- 3
= 2-√3 /1.
hence answer is 2-√3
hope it helps
thank you
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Anonymous:
thank you
Answered by
2
Hello Dear!!!
Here's your answer....
Here's your answer....
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