Question

An object travels 10 m in 4 s and then another 14 m in 2 s. What is the average speed of the object?​

Answer 1

Answer:

Given -

• An object travels 10 m in 4s at first
• and, another 14 m in 2s

To find -

• Average speed of the object.

Solution -

Total distance travelled = 10 m + 14 m = 24 m

Total time taken = 4s + 2s = 6s

Average speed = Total distance travelled / total time taken

→ 24m / 6s

→ 4m/s

Therefore, the average speed of the object is 4m/s.

Answer 2

Answer:

4 m/s

Explanation:

Given that an object travels 10 m in 4 s and then another 14 m in 2 s.

Firstly it travels 10 m in 4 s and then 14 m in 2 s in another half. d1 = 10 m, t1 = 4 s, d2 = 14 m and t2 = 2 s (say).

Average speed = (Total distance covered)/(Tota time taken)

Total distance covered = d1 + d2

= 10 + 14

= 24 m

Total time taken = t1 + t2

= 4 + 2

= 6 s

Now,

Average speed = 24/6 = 4

Hence, the average speed of the object is 4 m/s.