An object travels 16 m in 4 second and another 14 min 2 second, the avarage speed of object is :- A: 5.33 ms-1 B: 6 ms-1 C: 5 ms-1 D: 5.5 ms-1
Answers
Answer :-
- Average speed of the object is C. 5 m/s.
Explanation :-
Given :
- Distance₁ = 16 m
- Distance₂ = 14 m
- Time₁ = 4 sec
- Time₂ = 2 sec
To find :
- Average speed
Solution :
Average speed :
- Total distance/Total time
Substituting we get,
⇒ (16 + 14)m/(4 + 2)s
⇒ 30m/6s
⇒ 5 m/s
- The average speed of the object is 5 m/s.
Answer:
Now in the above case :-
Total Distance Covered = 16 + 16 = 32 m
Total Time Taken to Travel 32m = 4 + 2 = 6 s
Thus The Average Speed of the Moving Object = 32 ÷ 6 = 5.33 m/s
This is different from the Mathematical Average of Speeds
Speed of the object in first case = 16 ÷4 = 4 m / s
Speed of the object in second case = 16 ÷ 2 = 8 m / s .
Mathematical Average of Speeds = ( 4 + 8 ) ÷ 2 = 12 / 2 = 6 m / s .
Now if you are said to determine AVERAGE OF SPEEDS , then you have to calculate the Mathematical Average . But if you are told to determine the Average Speed ( as told to you in this problem ) of the moving object , you have to apply the formula of Average Speed as Total Distance Travelled by the Moving Object divided by the Total Time Taken to Travel The Total Distance . Your answer in this case will be 5. 33 m/:s and not 6 m / s ..