Question

an object travels 16m in 4sec and then another 16m in 2 sec . what is the average speed of the object?​

Answer 1

Answer:

Total distance covered S=16+16=32 m

Total time t=4+2=6 s

Average speed V

avg

=

t

S

=

6

32

=5.33 m/s

Answer 2

Explanation:

speed in 1st 4 seconds=16/4=4m/s

speed in next 2 seconds=16/2=8m/s

∴ avg. speed=v1+v2/2

∴ avg. speed=4+8/2=12/2=6m/s

∴ avg. speed=6m/s

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