Question

an object travels 200m towards x-axisand return back 80m along thesame axis then the ratio of distance and magnitude of displacement will be​

Answer 1

Given :-

▪ An object travels 200 m along the x-axis anx return back 80 m along the same axis.

To Find :-

▪ Ratio of Distance travelled and the displacement

Solution :-

We know,

Distance is the total distance travelled by a body while Displacement is the difference between the final and initial position of a body.

Given, That the body travelled 200 m along the x-axis and then 80 m (No matter in which direction)

So,

⇒ Total distance travelled = 200 + 80

⇒ Total distance travelled = 280 m

As we know Displacement is the difference between the final and initial position so, given that the body first travelled 200 m in positive x-axis and then return back 80 m along the same axis.

So,

⇒ Displacement = 200 - 80

⇒ Displacement = 120 m

Now, Ratio of Distance to displacement can be calculated as,

⇒ Distance / Displacement

⇒ 280 / 120

⇒ 28 / 12

⇒ 14 / 6

⇒ 7 / 3

Hence, The ratio of the distance travelled to the displacement made is 7 : 3

Answer 2

Answer:

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⠀

Let the Object starts Travelling from Point O and travelled distance 200 metres to reach Point A then return to Point B by travelling 80 metres.

⠀

• Total Distance Travelled :

⇒ Distance = OA + AB

⇒ Distance = 200 m + 80 m

⇒ Distance = 280 m

⠀

• Displacement of the Object :

• Displacement is the shortest distance travelled between Starting Point and Finishing Point.

⇒ Displacement = OB

⇒ Displacement = OA - AB

⇒ Displacement = 200 m - 80 m

⇒ Displacement = 120 m

$\rule{180}{1.5}$

$\underline{\bigstar\:\textsf{According to the given Question :}}$

$:\implies\sf \dfrac{Distance}{Displacement} = \dfrac{280 \:m}{120 \:m}\\\\{\scriptsize\qquad\bf{\dag}\:\:\frak{Dividing\:\:both\:\:term\:\:by\:\:40}}\\\\:\implies\sf \dfrac{Distance}{Displacement} = \dfrac{7}{3}\\\\\\:\implies\underline{\boxed{\sf Distance: Displacement=7:3}}$