An object travels a distance of 16m in 4se and another 16m in 2se what is the average speed of the object?
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Answered by
2
Av speed = total distance travelled / total time taken
Av speed = (16+16)/(4+2)
= 32/6
= 16/3 ms¯¹
Av speed = (16+16)/(4+2)
= 32/6
= 16/3 ms¯¹
Answered by
1
speed = distance/time
first speed of object = 16/4
= 4 m/s
second speed of object = 16/2
= 8 m/s
therefore, the average speed of object = (4+8)/2
= 12/2
= 6m/s
first speed of object = 16/4
= 4 m/s
second speed of object = 16/2
= 8 m/s
therefore, the average speed of object = (4+8)/2
= 12/2
= 6m/s
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