Question

An object travels a distance of 16m in 4se and another 16m in 2se what is the average speed of the object?

Answer 1

Average speed=total distance travelled/total time required

=16+16/4+2

=32/6

=16/3m/s

Answer 2

Let the first distance and the first time be d1 and t1 respectively
Let the second distance and the second time be d2 and t2 respectively

Then total distance travelled = d1 + d2 = 16 + 16 = 32 m
Then total time taken = t1 + t2 = 4 + 2 = 6 sec

Average speed = Total distance/Total time
= 32 / 6 = 16 / 3 = 5.3 m/sec

Answer. Average speed is 5.3 m/sec.

Hope it helps !!!