an object travels with a velocity of 5m/s for the first 10s and then with a velocity of 10m/s for the next 20s. what is the average speed
Answers
Answered by
2
Average speed = 2S/ t₁ + t₂
In 10 secs distance covered = 10 x5 = 50 m
In next 20 secs distance covered = 10 x 20 = 200m
Total distance = 200 + 50 = 250m
So average speed = 2 x 250 / 10 + 20 = 500/30 = 50/3 m/s
Hope This Helps You!
In 10 secs distance covered = 10 x5 = 50 m
In next 20 secs distance covered = 10 x 20 = 200m
Total distance = 200 + 50 = 250m
So average speed = 2 x 250 / 10 + 20 = 500/30 = 50/3 m/s
Hope This Helps You!
Answered by
1
average speed =total distance /total time
total time= 10+20=30s
total distance =s1+s2
where s1 =v1t1
given.V1=5m/s
T1=10s
S1=5(10)=50m
now,S2=V2 ×T2
given V2=10m/s
T2=20s
S2=10(20)= 200m
now average speed = 50+200/30
250/30
25/3 m/s
I hope this will help u :)
total time= 10+20=30s
total distance =s1+s2
where s1 =v1t1
given.V1=5m/s
T1=10s
S1=5(10)=50m
now,S2=V2 ×T2
given V2=10m/s
T2=20s
S2=10(20)= 200m
now average speed = 50+200/30
250/30
25/3 m/s
I hope this will help u :)
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