Question

An object undergoes an acceleration of 20m/s^2 starting from rest . find the distance travelled in 5 sec​

Answer 1

Answer:

Explanation:

Solution,

Here, we have

Initial velocity, u = 0 (As object starts from rest)

Acceleration, a = 20 m/s²

Time taken, t = 5 seconds

To Find,

Distance covered, s = ?

According to the 2nd equation of motion,

We know that

s = ut + 1/2 × at²

So, putting all the values, we get

⇒ s = ut + 1/2 × at²

⇒ s = 0 × 5 + 1/2 × 20 × 5²

⇒ s = 1/2 × 20 × 25

⇒ s = 10 × 25

⇒ s = 250 m

Hence, the distance traveled by the object is 250.

Answer 2

✯✯ QUESTION ✯✯

An object undergoes an acceleration of 20m/s^2 starting from rest . find the distance travelled in 5 sec..

━━━━━━━━━━━━━━━━━━━━

✰✰ ANSWER ✰✰

$\longmapsto\tt{Given\:Acceleration(a)={20m/s}^{2}}$

$\longmapsto\tt{Time\:Taken(t)=5\:sec}$

$\longmapsto\tt{Initial\:Velocity(u)=0}$

$\longmapsto\tt{Distance(s)=?}$

➥Using 2nd Eq. of Motion : -

$\longmapsto\tt{\small{\boxed{\bold{\bold{\red{\sf{s=ut+\dfrac{1}{2}{at}^{2}}}}}}}}$

➥Putting Values : -

$\longmapsto\tt{s=0(5)+\dfrac{1}{2}\times{(20){(5)}^{2}}}$

$\longmapsto\tt{s=0+\dfrac{1}{\cancel{2}}\times{{\cancel{20}}(25)}}$

$\longmapsto\tt{s=10\times{25}}$

$\red\longmapsto\:\large\underline{\boxed{\bf\green{s}\orange{=}\purple{250m.}}}$

☛So , Distance travelled by the object is 250m.

_______________________

➜3 Equations of Motion : -

• v = u + at
• s = ut + 1/2 at²
• v²-u² = 2as

_______________________