Question

An object weighing 50 kg is lifted vertically through a height of 10 M. What is the work done?​

Answer 1

Answer:

No work is done.

Explanation:

W=Force×Distance×cos∅.

acceleration due to gravity(g)=10m/$s^{2}$.

distance=10m

∅=$90^{o}$

We know from the question that Weight of the object=50×10=500.

So work done=Force*Distance*cos∅

W=50*10*cos$90^{o}$=50*10*0=0(Since value of cos$90^{o}$=0).

If the angle between force and distance is 90 then the work done is 0.