Question

find the area of a quadrant of a circle whose circumference is 22cm.​

Answer 1

Answer:

a/q

$2 \times \pi \times r = 22 \\ 2 \times \frac{22}{7} \times r = 22 \\ r = \frac{7}{2}$

Area of quadrant of circle=

$\frac{1}{4} \times \frac{22}{7} \times {r}^{2} = \frac{22}{4 \times 7} \times {( \frac{7}{2} )}^{2} = \\ \frac{22 \times 7 \times 7}{4 \times 7 \times 2 \times 2} = \frac{77}{8} \: {cm}^{2} \\ ans.$

Answer 2

Answer:

Hope it's help u dear....