Question

- an object weighs 60 gm in air, 50 gm in water and 40 gm in oil. then the specific gravity of the oil will be _____. options:

Answer 1

Given :

Weight of silid in air=60gm

Weight of solid in water=50gm

Weight of solid in oil=40gm

Specific gravity=Relative density of liquid=?

Relative density of liquid
=loss of weight of solid in liquid/loss of weight of solid in water

=(60-40)/50

=20/50

=0.4
∴Specific gravity of oil is 0.4

Answer 2

Answer:

Step-by-step explanation:

The answer will be 2 not 0.4 becz

Specific gravity=density of object/density of water so when we divide it in that way we get the answer as 2