An object when placed at the front of a mirror forms an image 3 times the object whose focal lenght is 15 cm. Find object position?
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Explanation: given is magnification m= -v/u
v is image dist u is obj dist
then -v = 3u put in mirror formula
1/f = 1/v +1/u then 1/15 = -1/3u +1/u
then solving u get u= -10 cm
i.e, 10 cm to the left of mirror
PLZ MARK AS BRAINLIEST..........
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