Physics, asked by bigjohn9899, 1 year ago

An object with a mass of 1.5 kg changes its velocity from +15 m/s to +22 m/s during a time interval of 3.5 seconds. What impulse was delivered to the object?

Answers

Answered by TheGod
0
Impulse= mv-mu
so, here mv= 1.5×22
and mu= 1.5×15
therefore, I = m(v-u)
= 1.5(22-15)
= 1.5 × 7
= 10.5 N
Similar questions