Math, asked by vibhadudile60, 1 year ago

an object with a mass of 10 kg moves at a constant velocity of 10m/sec . a constant force then acts for 4 sec ob the object and gives it a speed of 2m/sec in opposite direction . the acceleration produced in it is ? ​

Answers

Answered by varaddaithankar
1

Answer:

2

Step-by-step explanation:

F=dp/dt

F=10*Accln

dp that is change in momentum=mv2-mv1

10(-2-10)=dp

dt=4sec

so Accln=(10*(-12))/40

=-3


vibhadudile60: ya
varaddaithankar: whats the formula
vibhadudile60: p = mv
varaddaithankar: Right Now just Remember this eqn force=change in momentum/t
vibhadudile60: ya
vibhadudile60: ok
vibhadudile60: I got
vibhadudile60: thx
vibhadudile60: thank you
vibhadudile60: actually my sis gave me task to do this I m in 6 the std
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