an object with a mass of 10 kg moves at a constant velocity of 10m/sec . a constant force then acts for 4 sec ob the object and gives it a speed of 2m/sec in opposite direction . the acceleration produced in it is ?
Answers
Answered by
1
Answer:
2
Step-by-step explanation:
F=dp/dt
F=10*Accln
dp that is change in momentum=mv2-mv1
10(-2-10)=dp
dt=4sec
so Accln=(10*(-12))/40
=-3
vibhadudile60:
ya
Similar questions
English,
6 months ago
Hindi,
6 months ago
Math,
6 months ago
English,
1 year ago
India Languages,
1 year ago