An object with constant acceleration has a velocity of v=10 m/s when it is at x+6m, and v =15m/s when it is at x= 10 m. What is its acceleration ?
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Hey.
Here is the answer.
at x = 6 m ; v = 10 m/s
at x = 10 m ; v = 15 m/s
So, s = final - initial position = 10-6= 4 m
Also,
![{v}^{2} - {u}^{2} = 2as {v}^{2} - {u}^{2} = 2as](https://tex.z-dn.net/?f=%7Bv%7D%5E%7B2%7D++-++%7Bu%7D%5E%7B2%7D++%3D+2as)
So,
![{15}^{2} - {10}^{2} = 2 \times a \times 4 {15}^{2} - {10}^{2} = 2 \times a \times 4](https://tex.z-dn.net/?f=+%7B15%7D%5E%7B2%7D++-++%7B10%7D%5E%7B2%7D++%3D+2+%5Ctimes+a+%5Ctimes+4)
or, 225 - 100 = 8a
or, 125 = 8a
so, a = 125 /8 = 15.625 m/s^2
Thanks .
Here is the answer.
at x = 6 m ; v = 10 m/s
at x = 10 m ; v = 15 m/s
So, s = final - initial position = 10-6= 4 m
Also,
So,
or, 225 - 100 = 8a
or, 125 = 8a
so, a = 125 /8 = 15.625 m/s^2
Thanks .
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