Question

an object with initial velocity 4m/s got its velocity tobe 40m/s after a time of 5 seconds. Find the force applied if mass of the object is 2 kg​

Answer 1

Given:-

→ Initial velocity of the object = 4 m/s

→ Final velocity = 40 m/s

→ Mass of the object = 2 kg

→ Time taken = 5 seconds

To find:-

→ Magnitude of force applied.

Solution:-

By Newton's 2nd law of motion, we know that :-

F = m(v - u)/t

Where :-

• F is the force.

• m is mass of the object.

• v is final velocity.

• u is initial velocity.

• t is time taken.

Substituting values, we get :-

⇒ F = 2(40 - 4)/5

⇒ F = 2(36)/5

⇒ F = 72/5

⇒ F = 14.4 N

Thus, the magnitude of force applied is 14.4 N .

Answer 2

Step-by-step explanation:

see your answer in image

answer is 14.4 9