Question

An object with length = 300 cm, width = 150 cm and height = 200 cm. The density of water is 1000 kg/m3. If the object is placed in the water, what is the buoyant force?​

Answer 1

Answer:

Buoyant force = 9000kgf

Explanation:

For an object,

length = 300 cm= 3m, width = 150 cm= 1.5m ,height = 200cm= 2 m

Volume of the object= (3*1.5*2)m = 9m^3

Buoyant force(F) = vol of the solid * density of water* g

(Substitute g as f )

F= 9m^3 * 1000 kg/m3 * f

F = 9000kgf