An object with mass 500 kg is lifted a height of 100 cm. what is the amount of work done in this case
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Answered by
4
Answer:
work=f × d
=m×g×h
=500×10×1
=5000Joule
Explanation:
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Answered by
1
Answer:
work=f × d
=m×g×h
=500×10×1
=5000Joule
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