An objectbis placed in front of a covex surface seperating two media of refractive index 1.1&1.5.The ratio of curvature is 50cm. Where is the image formed when object is placwd at a distance of 220cm?
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Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how fast velocity changes in meters per second squared (m/s^2). So by taking this formula the answer comes (m/s^2).
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