Question

an objects start moving from rest on a straight line path with uniform acceleration and covers distance of 100 m in first 10 s. the distance it cover in next 5s

Answer 1

Hey there,

Putting the assigned values in 2nd law of motion=s=ut+at²/2, we get-

100=100 a/2
So a=2 m/s²

Distance covered in 15 seconds from beginning=
s=at²/2=225 m

So the distance covered in next 5 seconds after 10 seconds of journey=
Distance covered in 15 seconds-Distance covered in 10 seconds
=225 m-100 m=125 m

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Regards
07161020
Ace

Answer 2

Hlo friend.. Cutiepie Here..

Nice question.

Here is ur answer :

From 2nd law of motion.

S= ut + 1/2 at²

100= 0×10 + 1/2 a(10)²

100= 1/2 a 100

a = 2m/s²

In 15 minutes

S = ut + 1/2 at²

S = 0 × 15 + 1/2×2×(15)²

S= 225m

For 5 minutes.

Distance covered in 15 minutes — Distance covered in 10 minutes

= 225m — 100m

= 125 m

An objects covers distance of 125m in next 5s.

HOPE IT HELPS YOU..

REGARDS
@sunita