Math, asked by abhinavdey740, 1 year ago

an oblong field 200 m long and 180 m wide has two cross road in its center the width of the longer roads is 4 m and shorter road is 3 m find the cost of watering the garden at 30 paisa per square meter

Answers

Answered by Debasish7
14
the ans of this is 10,398rupees
Attachments:
Answered by sk940178
29

10401.6 Rs.

Step-by-step explanation:

The area of the road across the garden is [(3 × 180) + (4 × 200) - (4 × 3)] = 1328 sq. meters.

Now, the area of the full rectangle with sides 200 m and 180 m is (200 × 180) = 36000 sq. meters.

Therefore, the area of the garden is (36000 - 1328) = 34672 sq. meters.

Now, the cost of watering the garden is 30 paisa per sq. meters i.e. 0.3 Rs. per sq, meters.

Therefore, the total cost of watering the garden will be (34672 × 0.3) = 10401.6 Rs. (Answer)

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