Question

an observer 1.5 m tall is 20.5 m away from a tower 22 m high .determine the angle of elevation of the top of the tower from the eye of the observer

Answer 1

From the figure (see the attached file kindly),
OB/BC=tanA
or, (22-1.5)/20.5=tanA
or, tanA=20.5/20.5
or, tanA=1
or, tanA=tan45°
or, A=45°
∴, the angle of elevation is 45°.

Answer 2

Answer:

Step-by-step explanation:

Let the height of observer is 1.5m

and tower is 22m

distance standing of observer is 20.5m

Now as per given

The height of tower will be 22-1.5m

because the observer height is 1.5m so it should be subtracted

Then the height of tower is 20.5m

Now to find angel of elevation we have height of tower and distance(base) so 20.5/20.5= 1

it will be TanA is=1 so according to the table tanA=1 means 45° angel of elevation is 45°