An observer, 1.5 m tall, is 28.5 m away from a high tower. Determine
the angle of elevation of the top of the tower form the eye of the observer,
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An observer, 1.5 m tall, is 28.5 m away from a high tower. Determine
the angle of elevation of the top of the tower form the eye of the observer,
Answered by
0
Answer:
= Height of the tower = AE= 30M
= Distance between the tower and the observer CD = EF = 28.5M
= Height of man DF = 1.5M
= CDEF is Rectangle
= Triangle ACD
= Tan Θ = AC / CD = AE - CE / CD = 30 - 1.5 / 28.5 = 1
= Tan = 1 -> Θ = 45°
hope it helps
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