Question

An observer, 1.5 m tall, is 28.5 m away from a tower 30 m high. Determine the angle of elevation of the tower from his eye.

Answer 1

.q

                               |

                  28.5m   |30m

    .p ___________ | .r

    |  1.5m                |

    |_____________|

(obs)    28.5m     (tower)

Let 'p' be the eye of observer and 'q' be the top of tower 

Let Angle of elevation be 'Ф' at 'p' towards 'q'

Tan Ф = opposite (rq)  = 30-1.5  = 1 

               adjacent(pr)       28.5 

Ф = 45 degrees

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