An observer 1.5m tall is 28.5m away from chimney .The angle of elevation top of the chimney for her eyes is 45 degrees what is the height of the chimney
Answers
Answered by
16
HEYAA..!!
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DC= BE = 28.5
DE=BC=1.5
In triangle AEB
tan 45= AB/BE
(tan 45= 1) 1 = AB/28.5
AB= 28.5 (cross multiplying)
AC= AB+BC
AC= 28.5+1.5
AC= 30 m
.
.
DC= BE = 28.5
DE=BC=1.5
In triangle AEB
tan 45= AB/BE
(tan 45= 1) 1 = AB/28.5
AB= 28.5 (cross multiplying)
AC= AB+BC
AC= 28.5+1.5
AC= 30 m
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Answered by
58
Answer✨✨
Let AB be the observer and CD be the tower also refer the given figure :
AC=BE=28.5m
AB=CE=1.5m,DE=h m
∴ From right angled △BED,
tan 45° = DE
BE ⇒1= h.
28.5
h=28.5
∴ Height of tower CD=h+1.5=28.5+
1.5=30 m
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